instead of using loops.
#include<stdio.h>
main()
{
int a, fact;
printf("\nEnter any number: ");
scanf ("%d", &a);
fact=rec (a);
printf("\nFactorial Value = %d", fact);
}
rec (int x)
{
int f;
if (x==1)
return (1);
else
f=x*rec(x-1);
return (f);
}
Beginner's C Programming Blog
#include<stdio.h>
main()
{
int a, fact;
printf("\nEnter any number: ");
scanf ("%d", &a);
fact=rec (a);
printf("\nFactorial Value = %d", fact);
}
rec (int x)
{
int f;
if (x==1)
return (1);
else
f=x*rec(x-1);
return (f);
}
#include<stdio.h>
main()
{
static int prev_number=0, number=1; // static: so value is not lost
int fibonacci (int prev_number, int number);
printf ("Following are the first 25 Numbers of the Fibonacci Series:\n");
printf ("1 "); //to avoid complexity
fibonacci (prev_number,number);
}
fibonacci (int prev_number, int number)
{
static int i=1; //i is not 0, cuz 1 is already counted in main.
int fibo;
if (i==25)
{
printf ("\ndone"); //stop after 25 numbers
}
else
{
fibo=prev_number+number;
prev_number=number; //important steps
number=fibo;
printf ("\n%d", fibo);
i++; // increment counter
fibonacci (prev_number,number); //recursion
}
}