Calculation of A to the power of B using Functions

Write a function power(a,b), to calculate the value of a raised to b.




#include<stdio.h>
main()
{

int power (a,b);
int a, b, result;

printf("Enter the value of a and b:");
scanf ("%d %d", &a, &b);

result=power(a,b);
printf("%d raised to %d is %d", a, b, result);

}

power (int a, int b)
{

int calculation=1, calc;
for (calc=1; calc <=b; calc++)

{
calculation=calculation*a;
continue;
}

return(calculation);
}





The File can be found at:
Download File

Comments

Niroop said…
may i know whether the CONTINUE statement is required,i think it is not,can u explain me dis plz
4:17 AM, November 13, 2009
Niroop said…
can anybody answer my question plzzz...
1:49 AM, November 19, 2009
surya said…
become a follower for free C,C++ And vb code of my blog:
http://www.a2zhacks.blogspot.com to learn C,C++,VB programming.
12:15 AM, January 05, 2010
Unknown said…
#include
#include
void roman(void);
main()
{
roman();
getch();
}
void roman()
{
int y,i;
printf("input the year to get its roman numeral:\n");
scanf("%d",&y);
for(i=1;i<=y;i++)
{if(y>=1000)
{
printf("m");
y=y-1000;}
}
for(i=1;i<=y;i++)
{if(y>=500)
{
printf("d");
y=y-500; }
}
for(i=1;i<=y;i++)
{if(y>=100)
{
printf("c");
y=y-100;}
}
for(i=1;i<=y;i++)
{if(y>=50)
{
printf("l");
y=y-50;}
}
for(i=1;i<=y;i++)
{if(y>=10)
{
printf("x");
y=y-10;}
}
for(i=1;i<=y;i++)
{if(y>=5)
{
printf("v");
y=y-5;}
}
for(i=1;i<=y;i++)
{if(y>=1)
{
printf("i");}
}
printf("\n");


}
9:39 AM, October 27, 2017
Unknown said…
#include
#include
void roman(void);
main()
{
roman();
getch();
}
void roman()
{
int y,i;
printf("input the year to get its roman numeral:\n");
scanf("%d",&y);
for(i=1;i<=y;i++)
{if(y>=1000)
{
printf("m");
y=y-1000;}
}
for(i=1;i<=y;i++)
{if(y>=500)
{
printf("d");
y=y-500; }
}
for(i=1;i<=y;i++)
{if(y>=100)
{
printf("c");
y=y-100;}
}
for(i=1;i<=y;i++)
{if(y>=50)
{
printf("l");
y=y-50;}
}
for(i=1;i<=y;i++)
{if(y>=10)
{
printf("x");
y=y-10;}
}
for(i=1;i<=y;i++)
{if(y>=5)
{
printf("v");
y=y-5;}
}
for(i=1;i<=y;i++)
{if(y>=1)
{
printf("i");}
}
printf("\n");


}
9:41 AM, October 27, 2017
Post a Comment

Popular posts from this blog

Matchstick Game using C Programming

Write a program for a matchstick game being played between the computer and a user. Your program should ensure that the computer always wins. Rules for the game are as follows: -There are 21 matchsticks. -The computer asks the player to pick 1, 2, 3 or 4 matchsticks. -After the person picks, the computer does its picking. -Whoever is forced to pick up the last matchstick loses the game. -There are 21 matchsticks. -Whoever is forced to pick up the last matchstick loses the game. So the last one is special, so it's all about how to get rid of 20 matches in pairs of turns. -The computer asks the player to pick 1, 2, 3 or 4 matchsticks. So if we reduce the total by 5 each round, the sequence will go 21 16 11 6 1 In effect, whatever number the user picks (n), the computer picks 5-n #include <stdio.h> main ( ) { int matchsticks = 21 , user , computer ; printf ( "Do not enter Invalid Numbers. \n Numbers above 4 are invalid." ) ; printf ( " \n If you do so, t...
Read more

C Program - Calculation of Area and Circumference of a Circle using Pointers

The following program is one good example that illustrates how we can return more than one value in a function. The answer is certainly using Pointers. The following program demonstrates the method. Write a function that calculates both Area and Perimeter/ Circumference of the Circle, whose Radius is entered through the keyboard. #include <stdio.h> main ( ) { int radius ; float area , perimeter ; printf ( " \n Enter radius of a circle:" ) ; scanf ( "%d" , & radius ) ; areaperi ( radius , & area , & perimeter ) ; printf ( "Area=%f" , area ) ; printf ( " \n Perimeter=%f" , perimeter ) ; } areaperi ( int r , float * a , float * p ) { * a = 3.14 * r * r ; * p = 2 * 3.14 * r ; } // This Program exhibits the use of Call By Reference . The program can be found at: Download File.
Read more

Calendar Program - Detecting the day on 1st Jan between 1900-19xx using if-else

This was the most tricky problem, and took me a lotta days to figure out what the solution would be like... According to the gregorian calendar, it was Monday on the date 01/01/1900. If any year is input through the keyboard write a program to find out what is the day on 1st January of this year. The following is an idea that was proposed for the solution: Assuming that you are not expected to come up with any date earlier than the one given. Your calculations can be fairly simple. * Calculate the number of days between your start date and the requested date * Find the remainder when you divide by seven * That will give you the day of the week, where monday == 0, tuesday == 1,..., Sunday == 6. So the crux of the problem is in step 1 Break this down into three parts * How many whole years between the start and and end dates * How many whole months between the start and end months * How many day between the start and end days Again the only tricky part is in the first s...
Read more