Any year is entered through the keyboard, write a program to
determine whether the year is leap or not.
(Use the logical operators && and ||)
#include<stdio.h>
main()
{
int year;
printf("Enter the year to check for a leap year:");
scanf ("%d", &year);
if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
{
printf("The entered year is a leap year.");
}
else
{
printf("The entered year is not a leap year.");
}
}
The file can be found at:
Download File
Monday, July 10, 2006
Subscribe to:
Post Comments (Atom)
6 comments:
simple and awesome
dat as grt...
mindblowing..............
perfect answer
Awesome answer.
Can you explain how u started thinking to solve the puzzle?
Thanks,
Subhankar.
I want c program for to find a leap year or not without using % and / operators.
this is hari
nhari425@gmail.com.
if u know the answer pls send to my mail...
thnk uuuuuu
Post a Comment