## Monday, June 26, 2006

### Reversing a Five Digit Number (Integer)

This program reverses a Five Digit number. The number is entered through the keyboard and worked upon by the program.

If a five-digit number is input through the keyboard, write a program to reverse the number.

/*Use an integer variable to store the reverse (say rev_num).
take out the first (rightmost) digit of the number.
Give it to rev_num.
Take out the 2nd digit from right.
Now multiply rev_num by 10 and add this new digit to it.
Do this till the last digit.

*/

/*To understand the program, assume that the five digit number -- 12345 is entered
Calculate the values manually and check against the given number.

The final result (reversed number) is going to be 54321*/

#include<stdio.h>
main()
{
int number, rev_num, next_digit,last_digit;

printf ("Enter the number that is to be reversed: ");
scanf("%d", &number);

last_digit = number - ((number / 10) * 10); /*units place*/

rev_num = last_digit; /* 5 */

next_digit = (number / 10) - ((number / 100) * 10); /*tenth's place*/

rev_num = (rev_num * 10) + next_digit; /*54*/

next_digit = (number / 100) - ((number / 1000) * 10); /*hundred's place*/

rev_num = (rev_num * 10) + next_digit; /*543*/

next_digit = (number / 1000) - ((number / 10000) * 10); /*thousand's place*/

rev_num = (rev_num * 10) + next_digit; /*5432*/

next_digit = (number / 10000) - ((number / 100000) * 10); /*ten thousand's place*/

rev_num = (rev_num * 10) + next_digit; /*54321*/

printf ("The Reversed Number is: %d",rev_num);
}

bijay said...

the explaination of the problem given here is very good and can be easily understood by begginers......

Anonymous said...

it's not giving proper result...When I am giving input 12345 it's giving -11215...please help me regarding this...

Anonymous said...

The program is absolutely wonderful to understand and execute

SHABEER said...

Nice Explanation...........

Anonymous said...

very nice ....its easy to understand

goyal said...

its ease to understand

Anonymous said...

Its really wonderful to understand...

JEET said...
This comment has been removed by the author.
JEET said...

Try This

main( )
{
int x,result,next;
printf("Enter The number to revers=");
scanf("%d",&x);
//5th
result=x%10;
result=result*10;
//4th
next=(x/10)%10;
result=(result+next)*10;
//3rd
next=(x/100)%10;
result=(result+next)*10;
//2nd
next=(x/1000)%10;
result=(result+next)*10;
//1st
next=(x/10000)%10;
result=result+next;
printf("%d",result);
}

imran khan said...

Both answers are totally wrong first check then publish

Anonymous said...

The best way of making this program is by using the while or for loop.its the shortest way of doing it

vijay said...

#include
int main(){
int num,d1,d2,d3,d4,d5,renum,sum;
printf("Enter a five digit number:");
scanf("%d",&num);
d1=num/10000;
d2=(num%10000)/1000;
d3=(num%1000)/100;
d4=(num%100)/10;
d5=num%10;
renum=d5*10000+d4*1000+d3*100+d2*10+d1;
sum=d1+d2+d3+d4+d5;
printf("Reverse number:%d\n",renum);
printf("Sum:%d",sum);
getch();
}

ashish said...

in dev c++ you should get the correct output
in turbo c++ there is error
if you type 12345 output will come as 11215
whereas in dev c++ and same coding
output is correct that is 54321.

imran safi said...

good explanation

Sam said...

#include
int main()
{
int num,a,b,c,d,e,aa,bb,cc,dd,ee;
printf("Enter the five digit number\n");
scanf("%d", &num);
e = num%10;
dd = num%100;
d = dd/10;
cc = num%1000;
c = cc/100;
bb = num%10000;
b = bb/1000;
aa = num%100000;
a = aa/10000;
printf("%d%d%d%d%d", e,d,c,b,a);

getchar();
getchar();
return 0;

}

Anonymous said...

this programs not properly execute.

m naeem said...

try this ..........so simple and easy
for more help contact me at
timcook_apple@yahoo.com

#include
void main()
{
int long x,p,q,r,s,t;
clrscr();
printf("\nEnter a 5-digit number:\n\t:");
scanf("%ld",&x);

p=x/10000;
q=(x/1000)-(p*10);
r=x/100-(p*100)-(q*10);
s=(x/10)-(p*1000)-(q*100)-(r*10);
t=x-(p*10000)-(q*1000)-(r*100)-(s*10);
printf("The reerse of given No:\n\t: %ld %ld %ld %ld %ld",t,s,r,q,p);

getche();
}

247 said...

I did it this way...

main()
{
int number, last_digit, prev_digit, total;

printf("Enter the number to be written in reverse: ");
scanf("%d", &number);

last_digit=number%10;
total=last_digit*10000;

prev_digit=(number/10)%10;
total=total+(prev_digit*1000);

prev_digit=(number/100)%10;
total=total+(prev_digit*100);

prev_digit=(number/1000)%10;
total=total+(prev_digit*10);

prev_digit=(number/10000)%10;
total=total+prev_digit;

printf("\nThe reverse of the enetered number is %d", total);

getch();
}

Daniyal Dani said...

#include
#include
#include
main()
{
int temp;
int rev=0;
cout<<"enter 5 digits to be reverse ";
cin>>temp;
for (int i=0;i<5;i++)
{
rev=(rev*10)+(temp%10);
temp/=10;
}
cout<<"reverse number is "<<rev;
getch();
}

Anonymous said...

I love this site. The programs r being explained in a very simple manner.

Hitesh Kumar said...

C++ Program to Reverse a Number

Reverse of number means reverse the position of all digits of any number. For example reverse of 536 is 635