This program reverses a Five Digit number. The number is entered through the keyboard and worked upon by the program.
If a five-digit number is input through the keyboard, write a program to reverse the number.
/*Use an integer variable to store the reverse (say rev_num).
take out the first (rightmost) digit of the number.
Give it to rev_num.
Take out the 2nd digit from right.
Now multiply rev_num by 10 and add this new digit to it.
Do this till the last digit.
*/
/*To understand the program, assume that the five digit number -- 12345 is entered
Calculate the values manually and check against the given number.
The final result (reversed number) is going to be 54321*/
#include<stdio.h>
main()
{
int number, rev_num, next_digit,last_digit;
printf ("Enter the number that is to be reversed: ");
scanf("%d", &number);
last_digit = number - ((number / 10) * 10); /*units place*/
rev_num = last_digit; /* 5 */
next_digit = (number / 10) - ((number / 100) * 10); /*tenth's place*/
rev_num = (rev_num * 10) + next_digit; /*54*/
next_digit = (number / 100) - ((number / 1000) * 10); /*hundred's place*/
rev_num = (rev_num * 10) + next_digit; /*543*/
next_digit = (number / 1000) - ((number / 10000) * 10); /*thousand's place*/
rev_num = (rev_num * 10) + next_digit; /*5432*/
next_digit = (number / 10000) - ((number / 100000) * 10); /*ten thousand's place*/
rev_num = (rev_num * 10) + next_digit; /*54321*/
printf ("The Reversed Number is: %d",rev_num);
}
Subscribe to:
Post Comments (Atom)
19 comments:
the explaination of the problem given here is very good and can be easily understood by begginers......
it's not giving proper result...When I am giving input 12345 it's giving -11215...please help me regarding this...
The program is absolutely wonderful to understand and execute
Nice Explanation...........
very nice ....its easy to understand
its ease to understand
Its really wonderful to understand...
Try This
main( )
{
int x,result,next;
printf("Enter The number to revers=");
scanf("%d",&x);
//5th
result=x%10;
result=result*10;
//4th
next=(x/10)%10;
result=(result+next)*10;
//3rd
next=(x/100)%10;
result=(result+next)*10;
//2nd
next=(x/1000)%10;
result=(result+next)*10;
//1st
next=(x/10000)%10;
result=result+next;
printf("%d",result);
}
Both answers are totally wrong first check then publish
The best way of making this program is by using the while or for loop.its the shortest way of doing it
#include
int main(){
int num,d1,d2,d3,d4,d5,renum,sum;
printf("Enter a five digit number:");
scanf("%d",&num);
d1=num/10000;
d2=(num%10000)/1000;
d3=(num%1000)/100;
d4=(num%100)/10;
d5=num%10;
renum=d5*10000+d4*1000+d3*100+d2*10+d1;
sum=d1+d2+d3+d4+d5;
printf("Reverse number:%d\n",renum);
printf("Sum:%d",sum);
getch();
}
in dev c++ you should get the correct output
in turbo c++ there is error
if you type 12345 output will come as 11215
whereas in dev c++ and same coding
output is correct that is 54321.
good explanation
#include
int main()
{
int num,a,b,c,d,e,aa,bb,cc,dd,ee;
printf("Enter the five digit number\n");
scanf("%d", &num);
e = num%10;
dd = num%100;
d = dd/10;
cc = num%1000;
c = cc/100;
bb = num%10000;
b = bb/1000;
aa = num%100000;
a = aa/10000;
printf("%d%d%d%d%d", e,d,c,b,a);
getchar();
getchar();
return 0;
}
this programs not properly execute.
try this ..........so simple and easy
for more help contact me at
timcook_apple@yahoo.com
#include
void main()
{
int long x,p,q,r,s,t;
clrscr();
printf("\nEnter a 5-digit number:\n\t:");
scanf("%ld",&x);
p=x/10000;
q=(x/1000)-(p*10);
r=x/100-(p*100)-(q*10);
s=(x/10)-(p*1000)-(q*100)-(r*10);
t=x-(p*10000)-(q*1000)-(r*100)-(s*10);
printf("The reerse of given No:\n\t: %ld %ld %ld %ld %ld",t,s,r,q,p);
getche();
}
I did it this way...
main()
{
int number, last_digit, prev_digit, total;
printf("Enter the number to be written in reverse: ");
scanf("%d", &number);
last_digit=number%10;
total=last_digit*10000;
prev_digit=(number/10)%10;
total=total+(prev_digit*1000);
prev_digit=(number/100)%10;
total=total+(prev_digit*100);
prev_digit=(number/1000)%10;
total=total+(prev_digit*10);
prev_digit=(number/10000)%10;
total=total+prev_digit;
printf("\nThe reverse of the enetered number is %d", total);
getch();
}
#include
#include
#include
main()
{
int temp;
int rev=0;
cout<<"enter 5 digits to be reverse ";
cin>>temp;
for (int i=0;i<5;i++)
{
rev=(rev*10)+(temp%10);
temp/=10;
}
cout<<"reverse number is "<<rev;
getch();
}
Post a Comment